Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Test - Page 535: 10b

Answer

True

Work Step by Step

$Sin^{2}α=(\frac{Opposite Side Of \angleα}{Hypotenuse})^{2}=\frac{a^{2}}{c^{2}}$ $Cos^{2}α=(\frac{Adjacent Side Of \angleα}{Hypotenuse})^{2}=\frac{b^{2}}{c^{2}}$ Now, Adding the two values, we get: $\frac{a^{2}}{c^{2}}+\frac{b^{2}}{c^{2}}=\frac{a^{2}+b^{2}}{c^{2}}$ By Pythagorean Theorem we know: $a^{2}+b^{2}=c^{2}$ Substituting $c^{2}$ in the previous equation, we get: $\frac{a^{2}+b^{2}}{c^{2}}=\frac{c^{2}}{c^{2}}$ $\frac{c^{2}}{c^{2}}=1$ Therefore, $Sin^{2}α+Cos^{2}α=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.