Answer
$35^{\circ}$
Work Step by Step
The length of the diagonal of the base of a cube is equal to $\sqrt2 s$. Thus, we find:
$tan(\alpha) = \frac{s}{\sqrt{2}s} \\ \alpha = \tan^{-1}( \frac{1}{\sqrt2}) = 35^{\circ}$
Elementary Geometry for College Students (5th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
1439047901
ISBN 13:
978-1-43904-790-3
Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 519: 40
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