#### Answer

$35^{\circ}$

#### Work Step by Step

The length of the diagonal of the base of a cube is equal to $\sqrt2 s$. Thus, we find:
$tan(\alpha) = \frac{s}{\sqrt{2}s} \\ \alpha = \tan^{-1}( \frac{1}{\sqrt2}) = 35^{\circ}$

Published by
Brooks Cole

ISBN 10:
1439047901

ISBN 13:
978-1-43904-790-3

$35^{\circ}$

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