Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises: 40

Answer

$35^{\circ}$

Work Step by Step

The length of the diagonal of the base of a cube is equal to $\sqrt2 s$. Thus, we find: $tan(\alpha) = \frac{s}{\sqrt{2}s} \\ \alpha = \tan^{-1}( \frac{1}{\sqrt2}) = 35^{\circ}$
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