Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 517: 7

Answer

$\sin\alpha=\frac{a}{c}$ $\cos\alpha=\frac{b}{c}$ $\tan\alpha=\frac{a}{b}$ $\csc\alpha=\frac{c}{a}$ $\sec\alpha=\frac{c}{b}$ $\cot\alpha=\frac{b}{a}$

Work Step by Step

$\sin\alpha=\frac{opposite}{hypotenuse}=\frac{a}{c}$ $\cos\alpha=\frac{adjacent}{hypotenuse}=\frac{b}{c}$ $\tan\alpha=\frac{opposite}{adjacent}=\frac{a}{b}$ $\csc\alpha=\frac{hypotenuse}{opposite}=\frac{c}{a}$ $\sec\alpha=\frac{hypotenuse}{adjacent}=\frac{c}{b}$ $\cot\alpha=\frac{adjacent}{opposite}=\frac{b}{a}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.