Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 511: 40

Answer

$ L = \frac{6}{cos\theta} + \frac{6}{sin\theta}$

Work Step by Step

We find each individual lengths. (In order to do this problem, you must remember that vertical angles are congruent.) Thus, we find: $sin \theta = \frac{6}{l_1} \\ l_1 =\frac{6}{sin \theta } $ And: $cos \theta = \frac{6}{l_2} \\ l_2 =\frac{6}{cos \theta } $ L is equal to $l_1$ plus $l_2$, so we find: $ L = \frac{6}{cos\theta} + \frac{6}{sin\theta}$
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