Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 503: 35a

Answer

$BE\approx5.4$ ft

Work Step by Step

$\sin65^{\circ}=\frac{BE}{6}$ $BE=6\sin65^{\circ}$ $BE\approx5.4$ ft

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