Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 502: 1

Answer

$\sin\alpha = \frac{5}{13}$ $\sin\beta = \frac{12}{13}$

Work Step by Step

$\sin\alpha=\frac{opposite}{hypotenuse}=\frac{5}{13}$ $\sin\beta=\frac{opposite}{hypotenuse}=\frac{12}{13}$
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