Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 10 - Section 10.2 - Graphs of Linear Equations and Slope - Exercises - Page 465: 33

Answer

It is a right triangle.

Work Step by Step

To be a right triangle, one set of slopes must be opposite reciprocals, for this would make two of the lines perpendicular. Thus: $m_1 = \frac{y_2-y_1}{x_2-x_1} = \frac{5-0}{6-(-3)} = 5/9$ $m_2 = \frac{y_2-y_1}{x_2-x_1} = \frac{5-(-2)}{6-4} =7/2 $ $m_3 = \frac{y_2-y_1}{x_2-x_1} = \frac{-2-0}{4-(-3)} = -2/7 $ Since slopes two and three are opposite reciprocals, it is a right triangle.
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