Answer
The medians of an isosceles triangle are equal in length.
Work Step by Step
We say that one corner of the triangle is at the origin, the base is of length a, and the two congruent sides are of length 2b. Thus:
$a^2 + b^2 = (d_1)^2$
$a^2 + b^2 = (d_2)^2$
It follows:
$(d_2)^2=(d_1)^2 \\ d_2=d_1$
Hence, the medians have equal lengths.
