Answer
x=60$^{\circ}$
m$\angle$1=120$^{\circ}$
Work Step by Step
By applying theorem 1.7.6 we know that $\angle$1 and $\angle$2 are supplementary
m$\angle$1+m$\angle$2=180$^{\circ}$
2x+x=180$^{\circ}$
3x=180$^{\circ}$
x=60$^{\circ}$
m$\angle$1=2x=2(60)=120$^{\circ}$
