#### Answer

$V = 1080~in^3$
$A = 636~in^2$

#### Work Step by Step

We can let the dimensions of the closed box be:
$W = 9~in$
$L = 10~in$
$H = 12~in$
We can find the volume:
$V = W \times L \times H = 9~in \times 10~in \times 12~in$
$V = 1080~in^3$
We can find the surface area:
$A = (2)(W \times L)+(2)(W \times H)+(2)(H \times L)$
$A = (2)(9~in \times 10~in)+(2)(9~in \times 12~in)+(2)(12~in \times 10~in)$
$A = 180~in^2+216~in^2+240~in^2$
$A = 636~in^2$