## Elementary Geometry for College Students (7th Edition)

$V = 1080~in^3$ $A = 636~in^2$
We can let the dimensions of the closed box be: $W = 9~in$ $L = 10~in$ $H = 12~in$ We can find the volume: $V = W \times L \times H = 9~in \times 10~in \times 12~in$ $V = 1080~in^3$ We can find the surface area: $A = (2)(W \times L)+(2)(W \times H)+(2)(H \times L)$ $A = (2)(9~in \times 10~in)+(2)(9~in \times 12~in)+(2)(12~in \times 10~in)$ $A = 180~in^2+216~in^2+240~in^2$ $A = 636~in^2$