#### Answer

147

#### Work Step by Step

We first find the necessary dimensions to find slant height. One leg of a 30-60-90 triangle with half of the base has length:
$3 \times (\frac{\sqrt3}{3}) = \sqrt{3}$
Thus, we obtain the value of the slant height:
$ h = \sqrt{(\sqrt3)^2 + 8^2 } = \sqrt{67}$
Thus, we find:
$ A = (1/2)(12)(\sqrt{67})(3)=147$