Answer
$$A =36\sqrt3+108$$
Work Step by Step
The area of the three squares is equal to:
$$ A =3A_{square} \\ = 3(6^2) \\ =108$$
The area of the equilateral triangle is:
$$ A = \frac{a^2\sqrt3}{4} \\ A=\frac{6^2\sqrt3}{4} \\ A=9\sqrt3$$
The isosceles trianges, in this case, have the same area. Thus, the total area is:
$$ A = 4\cdot 9\sqrt3 +108 \\ A =36\sqrt3+108$$
