# Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 377: 37

98.4

#### Work Step by Step

We assume the length of the first diagonal to be about: $2(8.2)=16.4$ The apothem is 12, and this is the other diagonal. Thus, we approximate area: $A = \frac{d_1d_2}{2} = \frac{16.4 \times 12}{2} \approx 98.4$

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