## Elementary Geometry for College Students (7th Edition)

We first cut the base into half by creating a diagonal of length 5 from the upper right hand corner. Next, knowing that the distance between this diagonal and the altitude that starts at the upper right hand corner is 3, we find: $h = \sqrt{5^2 - 3^2} = 4$ Using this, we find: $A = 1/2(b_1 + b_2)(h) = 1/2(16)(4)=32$