Elementary Geometry for College Students (7th Edition) Clone

4$\sqrt 29$m
In parallelogram if adjacent sides are equal then it will become rhombus In rhombus diagonals are perpendicular bisectors So if assume the point of intersection of both the diagonals as E, so EC = EA = 2m and BE = ED = 5m and $\angle$ CED = 90$^{\circ}$ By pythagoras theorem $CD^{2}$ =$CE^{2}$ + $ED^{2}$ = $5^{2}$ + $2^{2}$ = 25 + 4 = 29 CD = $\sqrt 29$ m As we know in rhombus all the sides are equal therefore AB=BC=CD=DA therefore perimeter = AB+BC+CD+DA = $\sqrt 29$+$\sqrt 29$+$\sqrt 29$+$\sqrt 29$ =4$\sqrt 29$m