Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 361: 53

Answer

48

Work Step by Step

We use trigonometry to obtain: $cos(30^{\circ}) = \frac{s}{8} \\ \\s = 8cos(30^{\circ})$ We square this to obtain: $A = (8cos(30^{\circ}))^2 = 48$
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