# Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 361: 53

48

#### Work Step by Step

We use trigonometry to obtain: $cos(30^{\circ}) = \frac{s}{8} \\ \\s = 8cos(30^{\circ})$ We square this to obtain: $A = (8cos(30^{\circ}))^2 = 48$

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