# Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 360: 40b

84 $cm^{2}$

#### Work Step by Step

The area of triangle whose base has length b and whose corresponding altitude has length h is given by A = $\frac{1}{2}$ bh In triangle ABC base b= 21 cm Height h = 8 cm. A =$\frac{1}{2}$ bh = $\frac{1}{2}$* 21 * 8 = 84 $cm^{2}$

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