Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 359: 22


18 $unit^{2}$

Work Step by Step

We need to find the area of the shaded region Area of the shaded region = area of the outer triangle - area of inner triangle Given A and B are mid points so for inner triangle b= 4 and h = 3 Area of triangle whose base has length b and altitude has length h is given by A = $\frac{1}{2}$ bh Area of outer triangle = $\frac{1}{2}$ *8* 6 = 24 $unit^{2}$ Area of inner triangle = $\frac{1}{2}$ * 4*3 = 6 $unit^{2}$ Area of the shaded region = 24 - 6 = 18 $unit^{2}$
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