## Elementary Geometry for College Students (7th Edition)

18 $unit^{2}$
We need to find the area of the shaded region Area of the shaded region = area of the outer triangle - area of inner triangle Given A and B are mid points so for inner triangle b= 4 and h = 3 Area of triangle whose base has length b and altitude has length h is given by A = $\frac{1}{2}$ bh Area of outer triangle = $\frac{1}{2}$ *8* 6 = 24 $unit^{2}$ Area of inner triangle = $\frac{1}{2}$ * 4*3 = 6 $unit^{2}$ Area of the shaded region = 24 - 6 = 18 $unit^{2}$