# Chapter 8 - Review Exercises - Page 396: 29

A=$\frac{8}{3}$$\pi-4\sqrt 3 #### Work Step by Step height of the triangle=.5s\sqrt 3 h=2\sqrt 3 base of the triangle=r=4 A=\frac{1}{6}$$\pi$4$^2$-$\frac{1}{2}$(4)(2$\sqrt 3$) A=$\frac{8}{3}$$\pi$-4$\sqrt 3$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.