Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Review Exercises - Page 395: 3



Work Step by Step

Since there are all 90 degree angles and since the sides of the shape are all congruent, it is a square. We know the diagonal creates a 45-45-90 triangle, so: $ s = 10 \times \frac{\sqrt{2}}{2} = 5\sqrt{2}$ Thus, we find area: $A=s^2 = (5\sqrt{2})^2 = 25 \times 2 = 50$
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