Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Section 6.3 - Line and Segment Relationships in the Circle - Exercises - Page 304: 4

Answer

OR=4$\sqrt 3$$\approx$6.9

Work Step by Step

RV=2m$\angle$S RV=2(15)=30$^{\circ}$ m$\angle$ROT=RV m$\angle$ROT=30$^{\circ}$ m$\angle$OTR=90$^{\circ}$ OTR is a 30 60 90 triangle. TR=$\frac{TO}{\sqrt 3}$ TR=$\frac{6\sqrt 3}{3}$ TR=2$\sqrt 3$ OR=2TR OR=4$\sqrt 3$$\approx$6.9
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