Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Section 6.1 - Circles and Related Segments and Angles - Exercises - Page 286: 24a


$5(30)=150 ^{\circ}$

Work Step by Step

We know that the angle between each each number on the clock is: $ \frac{360}{12}=30^{\circ}$ Here, the distance between the hands, given by the number of numbers between them, is: 5 Thus, the angle is: $5(30)=150 ^{\circ}$
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