## Elementary Geometry for College Students (7th Edition)

$c=\sqrt 41$
Using Pythagorean's Theorem... $a^{2}+b^{2}=c^{2}$ Substitute in known lengths... $5^{2}+4^{2}=c^{2}$ Simplify... $25+15=c^{2}$ $41=c^{2}$ Square root both sides... $\sqrt 41=c$