Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 268: 19

Answer

$\angle$QNM=41$^{\circ}$

Work Step by Step

NQ bisects $\angle$N because $\frac{NP}{PQ}$=$\frac{NM}{MQ}$ $\angle$N=180-$\angle$M-$\angle$P $\angle$N=180-36-62 $\angle$N=82 2$\angle$QNM=$\angle$N $\angle$QNM=41
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