## Elementary Geometry for College Students (7th Edition) Clone

By Pythagoras Theorem $(2x+3)^{2} = (2x+2)^{2} +x^{2}$ $4x^{2}+9+12x = 4x^{2} +4+8x+x^{2}$ $x^{2} -4x-5 = 0$ $x^{2} -(5-1)x-5 = 0$ $x^{2} -5x+x-5 = 0$ $x(x-5)+1(x-5)$ $(x-5)(x+1)=0$ x=5 that is correct x=-1 that is not possible because length can not be negative (2x+3) = 13 (2x+2)= 12