Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.3 - Proving Lines Parallel - Exercises - Page 245: 35

Answer

The proof is in the following form: Column 1 of proof; Column 2 of proof. Thus, we have: 1. Triangles DEF and MNP are similar, and DG and MQ are the altitudes; Given 2. Angle E is congruent to angle N; CASTC 3. Angle EGD and angle NQM are 90 degrees; perpendicular lines form right angles 4. Angle EGD is congruent to angle NQM; right angles are congruent 5. Triangle EDG is congruent to triangle NMQ; AA 6. $\frac{DG}{MQ} = \frac{DE}{MN}$; CSSTP
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.