Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Review Exercises - Page 273: 8g

Answer

$x = 6, -1$

Work Step by Step

$\frac{x-1}{x+2} = \frac{10}{3x-2}$ $(x-1)(3x-2) = 10(x+2)$ $x(3x-2) -1(3x-2) = 10x +20$ $3x^{2}- 2x -3x +2 = 10x +20$ $3x^{2} - 5x +2 = 10x +20$ $3x^{2} -5x + 2 -10x -20 = 0$ $3x^{2} -15x -18 = 0$ $3(x^{2} - 5x - 6) = 0$ $3(x-6)(x+1) = 0$ $x = 6, -1$
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