Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 4 - Section 4.3 - The Rectangle, Square, and Rhombus - Exercises - Page 206: 44


BE=$\sqrt {68}$$\approx$8.2

Work Step by Step

DE$^{2}$+AD$^{2}$=AE$^{2}$ DE$^{2}$=10$^{2}$-8$^{2}$ DE=6 CE=CD-DE CE=8-6 CE=2 BC$^{2}$+CE$^{2}$=BE$^{2}$ 8$^{2}$+2$^{2}$=BE$^{2}$ BE=$\sqrt {68}$$\approx$8.2
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