## Elementary Geometry for College Students (7th Edition)

altitude of an isosceles triangle = h =8cm perimeter = p =32cm and side = a cm then h =$1\div$2$\sqrt (p(4a-p))$ 16 = $\sqrt (32(4a-32))$ 16 = 8 $\sqrt(2a-16)$ 2= $\sqrt(2a-16)$ 4= 2a-16 2a=20 a= 10 cm