Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 3 - Section 3.2 - Corresponding Parts of Congruent Triangles - Exercises - Page 151: 15

Answer

1. $HJ$ bisects $\angle KHL$ 2. The bisector of an angle divides it into 2 congruent angles. 3. Given 4. A perpendicular line creates 2 corresponding right angles, which make them congruent with each other. 5. $\overline{HJ}\cong\overline{HJ}$ 6. $\triangle HJK\cong\triangle HJL$ 7. CPCTC.

Work Step by Step

1. Given Since the reason states Given, the statement must be something already mentioned in the given information part. Now, take a look at 2. $\angle JHK\cong\angle JHL$, which must be the result of the statement in 1. These congruent angles give us an intuition that $HJ$ bisects $\angle KHL$, which is exactly what is mentioned in the given information part. So, $HJ$ bisects $\angle KHL$ is what to be filled in 1. 2. $\angle JHK\cong\angle JHL$ As mentioned above, this is the result of the statement in 1. $HJ$ bisects $\angle KHL$, which makes two resulting angles congruent with each other. Therefore, we would fill here 2. The bisector of an angle divides it into 2 congruent angles. 3. $\overline{HJ}\bot\overline{KL}$ This statement is already mentioned in the given information part. So, we would fill here 3. Given. 4. $\angle HJK\cong\angle HJL$ Since $\overline{HJ}\bot\overline{KL}$, two resulting angles $\angle HJK$ and $\angle HJL$ must be right angles. And since they are two corresponding right angles, they must be congruent with each other. Here we would fill 4. A perpendicular line creates 2 corresponding right angles, which make them congruent with each other. 5. Identity The reason mentioned Identity. So we would look a line that 2 triangles share. Here only line $\overline{HJ}$ are shared by both $\triangle HJK$ and $\triangle HJL$. So $\overline{HJ}$ is the only choice to have here. Therefore, we would fill 5. $\overline{HJ}\cong\overline{HJ}$ 6. ASA Throughout the whole process above, we've got 2 angles and the included side of $\triangle HJK$ are congruent with 2 corresponding angles and the included side of $\triangle HJL$, which is also method ASA. So now, we can conclude $\triangle HJK\cong\triangle HJL$ by method ASA to fill in 6. 7. $\angle K\cong\angle L$ We conclude above that $\triangle HJK\cong\triangle HJL$. $\angle K$ and $\angle L$ are 2 corresponding angles of $\triangle HJK$ and $\triangle HJL$ respectively. Therefore, to show $\angle K\cong\angle L$, we would use method CPCTC. So, to fill here 7. CPCTC.
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