## Elementary Geometry for College Students (7th Edition) Clone

Using method SAS for 2 congruent pairs of sides and 1 congruent pair of included angles, we can prove that $\triangle ABC\cong\triangle DBC$.
It is given that - $\overline{AB}\cong\overline{BD}$ - $\angle A\cong\angle D$ - $\overline{AC}\cong\overline{CD}$ We now have 2 sides and the included angle of $\triangle ABC$ are congruent with 2 sides and the included angle of $\triangle DBC$. Therefore, according to method SAS, $\triangle ABC\cong\triangle DBC$.