Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.5 - Convex Polygons - Exercises - Page 115: 29

Answer

$\angle$1 + $\angle$2 = $\angle$3 + $\angle$4 Hence proved

Work Step by Step

Sum of all angles of a quadrilateral = $360^{\circ}$ Sum of linear angles on a line = $180^{\circ}$ HENCE $\angle$SRQ + $\angle4 + \angle$QTS + $\angle$3= $360$ THUS (180- $\angle$1)+$\angle$4 + (180-$\angle$2) +$\angle$3=$360 \approx 360 + \angle$4 + $\angle$3 -$\angle$1 - $\angle$2 =$360$ since $ (360-360=0)$ BY taking all the negative terms to The Right = $\angle$1$ + $$\angle$2$ = $$\angle$3 + $\angle$4 Hence proved
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