Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Review Exercises - Page 533: 33

Answer

$\csc\theta=\frac{29}{20}$ $\sin\theta=\frac{20}{29}$

Work Step by Step

$\cot\theta=\frac{21}{20}$ $1+\cot^2\theta=\csc^2\theta$ $1+\frac{441}{400}=\csc^2\theta$ $\csc^2\theta=\frac{841}{400}$ $\csc\theta=\frac{29}{20}$ $\sin\theta=\frac{1}{\csc\theta}$ $\sin\theta=\frac{20}{29}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.