Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 10 - Section 10.2 - Graphs of Linear Equations and Slope - Exercises - Page 458: 12c


$\frac{8\sqrt 6}{\sqrt 2}$ =8$\sqrt 3$

Work Step by Step

(2$\sqrt 2$,-3$\sqrt 6$) and (3$\sqrt 2$,5$\sqrt 6$) x1=2$\sqrt 2$, y1=-3$\sqrt 6$,x2=3$\sqrt 2$,y2=5$\sqrt 6$ Using slope formula m = $\frac{y2-y1}{x2-x1}$ m= $\frac{5\sqrt 6+3\sqrt 6}{3\sqrt 2-2\sqrt 2}$ = $\frac{8\sqrt 6}{\sqrt 2}$ =8$\sqrt 3$
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