Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 1 - Section 1.2 - Angles and Their Relationships - Exercises - Page 48: 31

Answer

x=143$^{\circ}$

Work Step by Step

x=(90$^{\circ}$-$\angle$PNQ)+92$^{\circ}$ x=(90$^{\circ}$-39$^{\circ}$)+92$^{\circ}$ x=51$^{\circ}$+92$^{\circ}$ x=143$^{\circ}$
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