Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Appendix A - A.3 - Inequalities - Exercises - Page 551: 27

Answer

$x \leq -2$

Work Step by Step

$x^{2} + 4x\leq x(x-5)-18$ $x^{2} + 4x \leq x^{2} - 5x - 18$ $x^{2} - x^{2} + 4x + 5x + 18 \leq 0$ $9x + 18 \leq 0$ $9x \leq -18$ $x \leq -2$
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