Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 9 - Section 9.2 - Pyramids, Area, and Volume - Exercises - Page 409: 40

Answer

(a) The area of the base is $~~24~in^2$ (b) $altitude = 3.1~in$

Work Step by Step

(a) We can find the area of the base: $V = \frac{1}{3}~(base~area)(altitude)$ $base~area = \frac{3V}{altitude}$ $base~area = \frac{(3)(32~in^3)}{4~in}$ $base~area = 24~in^2$ The area of the base is $~~24~in^2$ (b) We can find the length of the altitude: $V = \frac{1}{3}~(base~area)(altitude)$ $altitude = \frac{3V}{base~area}$ $altitude = \frac{(3)(32~in^3)}{31.23~in^2}$ $altitude = 3.1~in$
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