Elementary Geometry for College Students (6th Edition)

(a) The area of the base is $~~24~in^2$ (b) $altitude = 3.1~in$
(a) We can find the area of the base: $V = \frac{1}{3}~(base~area)(altitude)$ $base~area = \frac{3V}{altitude}$ $base~area = \frac{(3)(32~in^3)}{4~in}$ $base~area = 24~in^2$ The area of the base is $~~24~in^2$ (b) We can find the length of the altitude: $V = \frac{1}{3}~(base~area)(altitude)$ $altitude = \frac{3V}{base~area}$ $altitude = \frac{(3)(32~in^3)}{31.23~in^2}$ $altitude = 3.1~in$