Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 9 - Section 9.1 - Prisms, Area, and Volume - Exercises - Page 397: 21

Answer

$V = 7500~cm^3$ $A = 2350~cm^2$

Work Step by Step

We can let the dimensions of the closed box be: $W = 15~cm$ $L = 20~cm$ $H = 25~cm$ We can find the volume: $V = W \times L \times H = 15~cm \times 20~cm \times 25~cm$ $V = 7500~cm^3$ We can find the surface area: $A = (2)(W \times L)+(2)(W \times H)+(2)(H \times L)$ $A = (2)(15~cm \times 20~cm)+(2)(15~cm \times 25~cm)+(2)(25~cm \times 20~cm)$ $A = 600~cm^2+750~cm^2+1000~cm^2$ $A = 2350~cm^2$
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