Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 366: 4b



Work Step by Step

First, we use the Pythagroean theorem to find: $4^2 = 2^2 + (\frac{x^2}{2^2}) \\ x^2 = 48$ We use the formula for area: $A = \frac{\sqrt3}{4}\times x^2\\A = \frac{\sqrt3}{4}\times 48 \\A= 20.8$
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