#### Answer

84 $in^{2}$

#### Work Step by Step

The area of triangle whose base has length b and whose corresponding altitude has length h is given by A = $\frac{1}{2}$ bh
In triangle ABC base b= 14 in.
Height h = 12 in.
A = $\frac{1}{2}$ bh
= $\frac{1}{2}$ 14 * 12
= 84 $in^{2}$