Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 7 - Test - Page 339: 15a


6.9 inches

Work Step by Step

If you connect point B to the midpoint, M, of AC it splits ABC into two 30 60 90 triangles. Short leg BM=.5(AB)=2 and long leg AM=2$\sqrt 3$. Diagonal AC is twice the length of AM, therefore AC=4$\sqrt 3$$\approx3$6.9
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