## Elementary Geometry for College Students (6th Edition)

a) BG = 12 b) GE = 2 c) DG = $8\sqrt3$
a) A theorem states that BG equals 2/3 of BF. Thus: $BG = 18 \times (2/3) = 12$ b) GE is half of AG. Thus: $GE = .5(4) = 2$ c) Using the same method as in b), we know that DG is twice the value of CG. Thus: $DG = 2 (4\sqrt{3}) = 8\sqrt3$