Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 6 - Section 6.3 - Line and Segment Relationships in the Circle - Exercises - Page 295: 4

Answer

OR=4$\sqrt 3$$\approx$6.9

Work Step by Step

RV=2m$\angle$S RV=2(15)=30$^{\circ}$ m$\angle$ROT=RV m$\angle$ROT=30$^{\circ}$ m$\angle$OTR=90$^{\circ}$ OTR is a 30 60 90 triangle. TR=$\frac{TO}{\sqrt 3}$ TR=$\frac{6\sqrt 3}{3}$ TR=2$\sqrt 3$ OR=2TR OR=4$\sqrt 3$$\approx$6.9
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