Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 6 - Section 6.2 - More Angle Measures in the Circle - Exercises - Page 287: 34


5.67 mm

Work Step by Step

We know that OE is 5 mm. In addition, since OE equals ED, and EF is half of ED, it follows that EF is half of 5, which is 2.5. Since OFE is a right angle, we use the Pythagorean theorem: $OF^2 + 2.5^2 = 5^2 \\ OF = 4.33 mm$ Since OF plus FC equals 10, this means that FC equals $10 - 4.33 = 5.67$.
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