#### Answer

$m\widehat {BC}=135^{\circ}$

#### Work Step by Step

If the $m\widehat {ACB}=270^{\circ}$, and point $C$ bisects arc $ACB$, then $m\widehat {BC}$ is half the $m\widehat {ACB}$ or $m\widehat {BC}=135^{\circ}$.

Published by
Brooks Cole

ISBN 10:

ISBN 13:

$m\widehat {BC}=135^{\circ}$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.