#### Answer

$m\widehat {BC}=135^{\circ}$

#### Work Step by Step

If the $m\widehat {ACB}=270^{\circ}$, and point $C$ bisects arc $ACB$, then $m\widehat {BC}$ is half the $m\widehat {ACB}$ or $m\widehat {BC}=135^{\circ}$.

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Published by
Brooks Cole

ISBN 10:
9781285195698

ISBN 13:
978-1-28519-569-8

$m\widehat {BC}=135^{\circ}$

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