#### Answer

m$\angle$A$\lt$m$\angle$C

#### Work Step by Step

Since the measure of a central angle is equal to the measure of its intercepted arc, angle AQB must be greater than angle CQD. Triangles AQB and CQD are isosceles triangles with radii for congruent sides. The larger the vertex angle of an isosceles triangle, the smaller the measure of the base angles. By this logic angle A must be smaller than angle C.