#### Answer

$\sqrt{45}$

#### Work Step by Step

We use the theorems in the chapter to obtain:
$EC CD = AC BC \\ 2ED(CD) = 3(30)$
We know CD and ED are equal, so we find:
$2ED^2 = 90 \\ ED = \sqrt{45}$

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Published by
Brooks Cole

ISBN 10:
9781285195698

ISBN 13:
978-1-28519-569-8

$\sqrt{45}$

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