Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 249: 35a


BF=6$\sqrt 3$

Work Step by Step

Since ABCDEF is a regular hexagon, the diagonals shown form a 30 60 90 triangle. CB=AB CB=6 BF=CB$\sqrt 3$ BF=6$\sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.