Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 249: 35a

Answer

BF=6$\sqrt 3$

Work Step by Step

Since ABCDEF is a regular hexagon, the diagonals shown form a 30 60 90 triangle. CB=AB CB=6 BF=CB$\sqrt 3$ BF=6$\sqrt 3$
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