Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.1 - Ratios, Rates, and Proportions - Exercises - Page 217: 39a



Work Step by Step

$\frac{5}{L}$=$\frac{L-5}{5}$ L$^2$-5L-25=0 L=$\frac{5+\sqrt {-5^2-4(-25)}}{2}$ L=$\frac{5+\sqrt {125}}{2}$ L$\approx$8.1
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