Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 4 - Section 4.3 - The Rectangle, Square, and Rhombus - Exercises - Page 195: 42


BE=$\sqrt {68}$$\approx$8.2

Work Step by Step

DE$^{2}$+AD$^{2}$=AE$^{2}$ DE$^{2}$=10$^{2}$-8$^{2}$ DE=6 CE=CD-DE CE=8-6 CE=2 BC$^{2}$+CE$^{2}$=BE$^{2}$ 8$^{2}$+2$^{2}$=BE$^{2}$ BE=$\sqrt {68}$$\approx$8.2
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