Answer
BE=$\sqrt {68}$$\approx$8.2
Work Step by Step
DE$^{2}$+AD$^{2}$=AE$^{2}$
DE$^{2}$=10$^{2}$-8$^{2}$
DE=6
CE=CD-DE
CE=8-6
CE=2
BC$^{2}$+CE$^{2}$=BE$^{2}$
8$^{2}$+2$^{2}$=BE$^{2}$
BE=$\sqrt {68}$$\approx$8.2
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 4 - Section 4.3 - The Rectangle, Square, and Rhombus - Exercises - Page 195: 42
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
