Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 4 - Section 4.3 - The Rectangle, Square, and Rhombus - Exercises - Page 195: 42

Answer

BE=$\sqrt {68}$$\approx$8.2

Work Step by Step

DE$^{2}$+AD$^{2}$=AE$^{2}$ DE$^{2}$=10$^{2}$-8$^{2}$ DE=6 CE=CD-DE CE=8-6 CE=2 BC$^{2}$+CE$^{2}$=BE$^{2}$ 8$^{2}$+2$^{2}$=BE$^{2}$ BE=$\sqrt {68}$$\approx$8.2
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.